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NCARB PDD 認定試験の出題範囲:
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NCARB ARE 5.0 Project Development and Documentation Exam 認定 PDD 試験問題 (Q86-Q91):
質問 # 86
The single-line diagram for the electrical distribution system shown is for a multi-family project.
Click in the box on the single-line diagram where the transformer is located.
正解:
解説:
Explanation:
The transformer is located in the first large box after the high-voltage primary feeders and before the secondary service conductors on the left side of the diagram.
Step-by-Step Reasoning
1. Understanding the diagram flow:
* The leftmost symbol represents high-voltage primary feeders from the utility (2,400V, 4,160V, 7,200 V, or 13,200V).
* Immediately after that, there is a large box labeled "Secondary Service conductors" with standard building service voltages (120/208, 120/240, 277/480 V).
* To get from primary (medium/high) voltage to these usable secondary voltages, you must step down the voltage - and that is done by a transformer.
2. Transformer location in electrical distribution:
* Transformers are always placed between the incoming primary service and the secondary distribution system in building diagrams.
* In this drawing, the transformer is symbolized by the first large square/rectangular box after the high- voltage primary feeders.
3. Why not any other box?
* The following boxes and lines after this first step are feeders, panels, and motor starters - they operate at secondary voltage.
* Only the transformer connects the utility high-voltage system to the building's lower-voltage system.
NCARB ARE 5.0 PDD References:
* Content Area: Electrical Systems - Service Entrance and Distribution
* Source References:
* MEEB (Mechanical and Electrical Equipment for Buildings) - Chapter on Transformers & Electrical Service
* NEC (National Electrical Code) Article 450 - Transformer Installation and Use
* Architectural Graphic Standards - Single-Line Diagrams for Electrical Distribution Key Point:
In building electrical distribution, the transformer is always between the high-voltage primary service and the secondary service conductors to step down voltage to a usable level for building loads.
質問 # 87
Owners of a busy two-story theater complex want to renovate. The new renovations include increasing the second floor lobby and doubling the number of second floor movie screens. The owner favors the use of escalators. Movies are scheduled to start simultaneously every three hours. The theater currently has a pair of
24-inch-wide parallel escalators, one of which goes up and the other down.
Which of the following should be proposed to accommodate the increased traffic to the second floor?
- A. Install a new escalator that reverses direction
- B. Install a new elevator in the lobby
- C. Extend balustrades at escalator landings
- D. Increase the existing escalator speeds to 130 fpm
正解:A
解説:
Given:
The theater doubles its second-floor movie screens, increasing patron traffic.
Existing escalators are two 24-inch wide units, one up and one down, with simultaneous movie start times every 3 hours.
To handle increased traffic:
Increasing existing escalator speed to 130 fpm (option A) is limited by safety and code limits (typically max around 100 fpm); also increases wear.
Installing a new elevator (option B) is helpful for accessibility but does not efficiently handle high flow of large crowds during peak.
Installing a new escalator that reverses direction (option C) (also called a "dance" or "two-way" escalator) allows flexibility to accommodate peak traffic flow-e.g., two escalators up during rush times and one down, or vice versa.
Extending balustrades (option D) improves safety but does not increase capacity.
Therefore, option C is the best solution to manage increased passenger flow.
References:
NCARB ARE 5.0 Review Manual, Environmental Systems and Building Services chapter Vertical transportation design principles in public assembly spaces ASME A17.1 Safety Code for Elevators and Escalators
質問 # 88
Which document is the most appropriate location for specifying the finish material for casework?
- A. Outline Specifications
- B. Construction Drawings
- C. General Conditions
- D. Project Manual - Division 06
正解:D
解説:
Division 06 (Wood, Plastics, and Composites) of the Project Manual contains detailed specifications for finish carpentry and casework materials. This aligns with ARE Objective 2.1: Evaluate project manual sections for technical accuracy.
質問 # 89
An architect needs to reduce the budget by $150,000 for a proposed civic auditorium. Currently the project requires the following flooring materials:
* Stained concrete: 100,000 square feet
* Carpet: 50,000 square feet
* Ceramic tile: 20,000 square feet
* Vinyl composite tile (VCT): 25,000 square feet
The flooring material costs are as follows:
* Stained concrete: $6.00/sq ft
* Sealed concrete: $2.00/sq ft
* Carpet: $8.75/sq ft
* Ceramic tile: $15.00/sq ft
* VCT: $5.75/sq ft
* Vinyl plank flooring: $7.00/sq ft
Which of the following combinations of changes results in these savings?
- A. Change 20,000 sq ft of stained concrete to VCT and substitute 10,000 sq ft of VCT for ceramic tile.
- B. Change 15,000 sq ft of VCT to vinyl plank flooring and substitute 10,000 sq ft of VCT for carpet.
- C. Change 25,000 sq ft of stained concrete to sealed concrete and substitute 30,000 sq ft of vinyl plank flooring for carpet.
- D. Change 20,000 sq ft of stained concrete to VCT and substitute 30,000 sq ft of vinyl plank flooring for carpet.
正解:A
解説:
Verified answer: C. Change 20,000 sq ft of stained concrete to VCT and substitute 10,000 sq ft of VCT for ceramic tile.
Comprehensive Detailed Explanation with all NCARB ARE 5.0 Project Development and Documentation (PDD) Study Guide References:
Calculate savings for each option by comparing current costs to proposed changes.
Verified answer: C. Change 20,000 sq ft of stained concrete to VCT and substitute 10,000 sq ft of VCT for ceramic tile.
Comprehensive Detailed Explanation with all NCARB ARE 5.0 Project Development and Documentation (PDD) Study Guide References:
Calculate savings for each option by comparing current costs to proposed changes.

Check if this matches required savings:
No, it's less than $150,000. So let's check others briefly.
Total savings = $100,000 + $52,500 = $152,500 # Meets and exceeds required savings
Options A and B will be less, so the answer should be D.
Summary:
Option D results in approximately $152,500 savings, meeting the $150,000 target.
Reference:
NCARB ARE 5.0 Review Manual, Project Cost Control and Materials chapter Construction cost estimating principles and value engineering strategies Change 20,000 sf stained concrete ($6.00/sf) to VCT ($5.75/sf) Savings per sf = $6.00 - $5.75 = $0.25 Total savings = 20,000 sf × $0.25 = $5,000 Substitute 10,000 sf of VCT ($5.75/sf) for ceramic tile ($15.00/sf) Savings per sf = $15.00 - $5.75 = $9.25 Total savings = 10,000 sf × $9.25 = $92,500 Total savings = $5,000 + $92,500 = $97,500 Check if this matches required savings:
No, it's less than $150,000. So let's check others briefly.
Option D:
Change 25,000 sf stained concrete ($6.00/sf) to sealed concrete ($2.00/sf) Savings per sf = $6.00 - $2.00 = $4.00 Total = 25,000 × 4.00 = $100,000 Substitute 30,000 sf vinyl plank ($7.00/sf) for carpet ($8.75/sf) Savings per sf = $8.75 - $7.00 = $1.75 Total = 30,000 × 1.75 = $52,500 Total savings = $100,000 + $52,500 = $152,500 # Meets and exceeds required savings Options A and B will be less, so the answer should be D.
Summary:
Option D results in approximately $152,500 savings, meeting the $150,000 target.
Reference:
NCARB ARE 5.0 Review Manual, Project Cost Control and Materials chapter Construction cost estimating principles and value engineering strategies
質問 # 90
In addition to reducing heat conductance, the thermal break in the construction of metal window frames does which of the following?
- A. Increases air infiltration
- B. Reduces the cost of manufacture
- C. Reduces condensation
- D. Increases sound transmission
正解:C
解説:
A thermal break in metal window frames interrupts the conductive path of heat through the frame, reducing heat transfer.
This reduces the chance that the interior surface of the frame will drop below the dew point temperature, thereby reducing condensation (surface moisture buildup).
Thermal breaks do not increase air infiltration; they help maintain thermal performance.
They reduce sound transmission, so B is incorrect.
Thermal breaks typically increase cost and complexity, so D is incorrect.
Reference:
NCARB ARE 5.0 Review Manual, Building Enclosure and Materials chapters
Fenestration performance and condensation control guides
質問 # 91
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